JEE Advanced Exam 2016 Paper-II Chemistry Question Paper With Answer Key

Part II : Chemistry

Section-1

• This section contains SIX questions.

• Each question has FOUR options (A), (B), (C) and (D). ONLY ONE of these four options is correct.

1. The correct order of acidity for the following compounds is

(A)   I > II > III > IV

(B)   III > I > II > IV

(C)   III > IV > II > I

(D)   I > III > IV > II

Answer: (A)

2. The major product of the following reaction sequence is

(A) 

(B)  

(C) 

(D)  

Answer: (A)

3. In the following reaction sequence in aqueous solution, the species X, Y and Z, respectively, are

(A)   [Ag(S2O3)2]3, Ag2S2O3, Ag2S

(B)   [Ag(S2O3)3]5, Ag2SO3, Ag2S

(C)   [Ag(SO3)2]3, Ag22O3, Ag

(D)   [Ag(SO3)3]3, Ag2SO4, Ag

Answer: (A)

4. The qualitative sketches I, II and III given below show the variation of surface tension with molar concentration of three different aqueous solutions of KCl, CH3OH and at room temperature. The correct assignment of the sketches is

(A)     

(B)     

(C)    

(D)    

Answer: (D)

5. The geometries of the ammonia complexes of Ni2+, Pt2+ and Zn2+, respectively, are

(A)   octahedral, square planar and tetrahedral

(B)   square planar, octahedral and tetrahedral

(C)   tetrahedral, square planar and octahedral

(D)   octahedral, tetrahedral and square planar

Answer: (A)

6. For the following electrochemical cell at 298 K,

Pt(s) | H2(g, 1 bar) | H+ (aq, 1M)|| M4+(aq), M2+ (aq) | Pt(s)

The value of x is

(A)   −2

(B)   −1

(C)   1

(D)   2

Answer: (D)

Section-2

• This section contains EIGHT questions.

• Each question has FOUR options (A), (B), (C) and (D). ONE OR MORE THAN ONE of these four option(s) is(are) correct.

7. According to Molecular Orbital Theory,

(A)     

(B)    

(C)     

(D)    

Answer: (A, C)

8. The CORRECT statement(s) for cubic close packed (ccp) three dimensional structure is(are)

(A)   The number of the nearest neighbours of an atom present in the topmost layer is 12

(B)   The efficiency of atom packing is 74%

(C)   The number of octahedral and tetrahedral voids per atom are 1 and 2, respectively

(D)   The unit cell edge length is 2√2 times the radius of the atom

Answer: (B, C, D)

9. Reagent(s) which can be used to bring about the following transformation is(are)

(A)   LiAlH4 in (C2H5)2O

(B)   BH3 in THF

(C)   NaBH4 in C2H­5OH

(D)   Raney Ni/H2 in THF

Answer: (C)

10. Extraction of copper from copper pyrite (CuFeS2) involves

(A)   crushing followed by concentration of the ore by froth-flotation

(B)   removal of iron as slag

(C)   self-reduction step to produce ‘blister copper’ following evolution of SO2

(D)   refining of ‘blister copper’ by carbon reduction

Answer: (A, B, C)

11. The nitrogen containing compound produced in the reaction of HNO3 with P4O10

(A)   can also be prepared by reaction of P4 and HNO3

(B)   is diamagnetic

(C)   contains one N-N bond

(D)   reacts with Na metal producing a brown gas

Answer: (B, D)

12. Mixture(s) showing positive deviation from Raoult’s law at 35℃ is (are)

(A)   carbon tetrachloride + methanol

(B)   carbon disulphide + acetone

(C)   benzene + toluene

(D)   phenol + aniline

Answer: (A, B)

13. For ‘invert sugar’, the correct statement(s) is (are)

(Given : specific rotations of (+)-sucrose, (+)-maltose, L-(−)-glucose and L-(+)-fructose in aqueous solution are +66°, +140°, −52° and +92°, respectively)

(A)   ‘invert sugar’ is prepared by acid catalyzed hydrolysis of maltose

(B)   ‘invert sugar’ is an equimolar mixture of D-(+)-glucose and D-(−)-fructose

(C)   specific rotation of ‘invert sugar’ is −20°

(D)   on reaction with Br2 water, ‘invert sugar’ forms saccharic acid as one of the products

Answer: (B, C)

14. Among the following, reaction(s) which gives(give) tert-butyl benzene as the major product is(are)

(A) 

(B) 

(C) 

(D) 

Answer: (B, C, D)

Section -3

• This section contains TWO paragraphs.

• Based on each paragraph, there are TWO questions.

• Each question has FOUR options (A), (B), (C) and (D). ONLY ONE of these four options is correct.

PARAGRAPH 1

Thermal decomposition of gaseous X2 to gaseous X at 298 K takes place according to the following equation : X2 (g) ⇌ 2X(g) .

The standard reaction Gibbs energy, ∆rG°, of this reaction is positive. At the start of the reaction, there is one mole of X2 and no X. As the reaction proceeds. the number of moles of X formed is given by β. Thus, β equilibrium is the number of moles of X formed at equilibrium. T he reaction is carried out at a constant total pressure of 2 bar. Consider the gases to behave ideally. (Given : R = 0.083 L bar K1 mol1)

15. The equilibrium constant Kp for this reaction at 298 K, in terms of β equilibrium , is

(A)    

(B)     

(C)    

(D)     

Answer: (B)

16. The INCORRECT statement among the following, for this reaction, is

(A)   Decrease in the total pressure will result in formation of more moles of gaseous X.

(B)   At the start of the reaction, dissociation of gaseous X2, takes place spontaneously.

(C)   β equilibrium  = 0.7.

(D)   KC < 1.

Answer: (C)

PARAGRAPH 2

Treatment of compound O with KMnO4/H+ gave P, which on heating with ammonia gave Q. The compound Q on treatment with Br2/NaOH produced R. On strong heating, Q gave S, which on further treatment with ethyl  2-bromopropanoate in the presence of KOH followed by acidification, gave a compound T.

17. The compound R is

(A)  

(B)   

(C)   

(D)  

Answer: (A)

18. The compound T is

(A)   glycine

(B)   alanine

(C)   valine

(D)   serine

Answer: (B)

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